y^2+50/25=160,002

Solution for y^2+50/25=160,002 equation:

y^2+50/25=160.002

We move all terms to the left:

y^2+50/25-(160.002)=0

We add all the numbers together, and all the variables

y^2-158.002=0

a = 1; b = 0; c = -158.002;
Δ = b2-4ac
Δ = 02-4·1·(-158.002)
Δ = 632.008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{632.008}}{2*1}=\frac{0-\sqrt{632.008}}{2}
=-\frac{\sqrt{}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{632.008}}{2*1}=\frac{0+\sqrt{632.008}}{2}
=\frac{\sqrt{}}{2}
$